\(a,PTHH:Zn+H_2SO_4\rightarrow ZnSO_4+H_2\\ n_{H_2}=\dfrac{2,479}{24,79}=0,1\left(mol\right)\\ \Rightarrow n_{Zn}=0,1\left(mol\right)\\ \Rightarrow m_{Zn}=0,1\cdot65=6,5\left(g\right)\\ b,n_{H_2SO_4}=n_{Zn}=0,1\left(mol\right)\\ \Rightarrow m_{CT_{H_2SO_4}}=0,1\cdot98=9,8\left(g\right)\\ \Rightarrow m_{dd_{H_2SO_4}}=\dfrac{9,8\cdot100\%}{10\%}=98\left(g\right)\)