Zn + CuSO4 \(\rightarrow\)ZnSO4 + Cu
mCuSO4=\(20.\dfrac{10}{100}=2\left(g\right)\)
nCuSO4=\(\dfrac{2}{160}=0,0125\left(mol\right)\)
Theo PTHH ta có:
nZn=nCuSO4=0,0125(mol)
mZn=65.0,0125=0,8125(g)
b;
Theo PTHH ta có:
nZn=nCu=0,0125(mol)
mCu=64.0,0125=0,8(g)