\(nSO_2=0,35mol\)
\(SO_2+Ca\left(OH\right)_2\rightarrow CaSO_3+H_2O\)
\(x.........x.............x\)
\(2SO_2+Ca\left(OH\right)\rightarrow Ca\left(HSO_3\right)_2\)
\(y..........\dfrac{y}{2}..............\dfrac{y}{2}\)
Ta có HPT:
\(x+y=0,35\)
\(120x+202.\dfrac{y}{2}=41,05\)
\(\Rightarrow x=0,3\&y=0,05\)
\(\Rightarrow nCa\left(OH\right)_2=x+\dfrac{y}{2}=0,325mol\)
\(\Rightarrow Cm=1,625M\)