Để (d1)//(d2) thì \(\left\{{}\begin{matrix}a=a'\\b\ne b'\end{matrix}\right.\)\(\Leftrightarrow\)\(\left\{{}\begin{matrix}-3k-2=k^2\\5-k\ne k+3\end{matrix}\right.\)\(\Leftrightarrow\)\(\left\{{}\begin{matrix}k^2+3k+2=0\\2k\ne2\end{matrix}\right.\)\(\Leftrightarrow\)\(\left\{{}\begin{matrix}\left(k+1\right)\left(k+2\right)=0\\k\ne1\end{matrix}\right.\)\(\Leftrightarrow\)\(\left\{{}\begin{matrix}\left[{}\begin{matrix}k=-1\\k=-2\end{matrix}\right.\\k\ne1\end{matrix}\right.\)\(\Leftrightarrow\)\(\left[{}\begin{matrix}k=-1\\k=-2\end{matrix}\right.\)