+) khi \(y=0\) ta có \(hs\Leftrightarrow\left(3-\sqrt{2}\right)x+2=0\Leftrightarrow x=\dfrac{-2}{3-\sqrt{2}}=\dfrac{2}{\sqrt{2}-3}\)
+) khi \(y=1\) ta có \(hs\Leftrightarrow\left(3-\sqrt{2}\right)x+2=1\Leftrightarrow x=\dfrac{-1}{3-\sqrt{2}}=\dfrac{1}{\sqrt{2}-3}\)