cho biểu thức
A=\(\left(\dfrac{x+4}{3x+6}-\dfrac{1}{x^2+4x+4}\right)\left(1+\dfrac{x-1}{x+5}\right)\)
a, rút gọn
b, tìm x để A có giá trị là số nguyên
bài 2 : rút gọn các biểu thức sau:
a,\(\dfrac{a+4\sqrt{a}+4}{\sqrt{a}+2}+\dfrac{4-a}{\sqrt{a}-2}\)(\(a\ge0;a\ne4\)
b, \(\left(\dfrac{a+b+2\sqrt{ab}}{\sqrt{a}+\sqrt{b}}-\sqrt[]{a}\right)\left(\dfrac{a-b}{\sqrt{a}+\sqrt{b}}\right)^2\)
help me
A=(\(\dfrac{\left(x+4\right)}{3\left(x+2\right)}-\dfrac{1}{\left(x+2\right)^2}\))(\(\dfrac{x+5+x-1}{x+5}\))
A=\(\dfrac{\left(x+4\right)\left(x+2\right)-3}{3\left(x+2\right)^2}\cdot\dfrac{2x+2}{x+5}\)
A=\(\dfrac{x^2+2x+4x+8-3}{3\left(x-2\right)}\cdot\dfrac{2}{x+5}\)
A=\(\dfrac{x^2+6x+5}{3\left(x-2\right)}\cdot\dfrac{2}{x+5}\)
A=\(\dfrac{x^2+6x+9-4}{3\left(x-2\right)}\cdot\dfrac{2}{x+5}\)
A=\(\dfrac{\left(x+3\right)^2-4}{3\left(x-2\right)}\cdot\dfrac{2}{x+5}\)
A=\(\dfrac{2\left(x+3-2\right)\left(x+3+2\right)}{3\left(x-2\right)\left(x+5\right)}\)
A=\(\dfrac{2\left(x+1\right)}{3\left(x-2\right)}\)
