a)
\(n_{H_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)
PTHH: \(Zn+2HCl\rightarrow ZnCl_2+H_2\)
0,1<---0,2<-------------0,1
\(\%Zn=\dfrac{0,1.65}{16,7}.100\%=38,922\%\)
\(\%Al_2O_3=100\%-38,922\%=61,078\%\)
b) \(n_{Al_2O_3}=\dfrac{16,7.61,078\%}{102}=0,1\left(mol\right)\)
PTHH: \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
0,1---->0,6
=> nHCl = 0,2 + 0,6 = 0,8 (mol)
=> mHCl = 0,8.36,5 = 29,2 (g)
=> \(m_{dd.HCl}=\dfrac{29,2.100}{20}=146\left(g\right)\)
=> \(V_{dd.HCl}=\dfrac{146}{1,1}=\dfrac{1460}{11}\left(cm^3\right)\)