OB//OD
\(\Rightarrow\widehat{ODB}=90^o\)
\(\widehat{AOB}và\widehat{BOC}\) là 2 góc kề bù
\(\Rightarrow\widehat{AOB}+\widehat{BOC}=180^o\)
\(\Rightarrow\widehat{COB}=180^o-40^o=140^o\)
Ta có : \(\widehat{BOD}+\widehat{COD}=\widehat{BOC}\)
\(\Rightarrow\widehat{COD}=140^o-90^o=50^o\)