\(n_{Cl_2}=\frac{5,6}{22,4}=0,25\left(mol\right)\)
\(PTHH:2KMnO_4+16HCl_{\left(đ\right)}\rightarrow2KCl+2MnCl_2+8H_2O+5Cl_2\)
(mol)_____2______________________________________________5___
(mol)_____0,1___________________________________________0,25__
\(m_{KMnO_4}=a=158.0,1=15,8\left(g\right)\)
PTHH:2KMnO4+16HCl->5Cl2+2MnCl2+2KCl+8H2O
mol:....2..........16.................5.........2............2...........8
mol:....0,1.........................0,25
nCl2=5,6:22,4=0,25(mol)
mKMnO4=0,1.158=15,8g
