Có : \(\dfrac{1}{2^2}\) < \(\dfrac{1}{4}\)
\(\dfrac{1}{3 ^2}\) < \(\dfrac{1}{2.3}\)
...
\(\dfrac{1}{2015^2}\) < \(\dfrac{1}{2014.2015}\)
\(\Rightarrow\) A< \(\dfrac{1}{4}\) + \(\dfrac{1}{2.3}\) + ... + \(\dfrac{1}{2014.2015}\)
= \(\dfrac{1}{4}\) + \(\dfrac{1}{2} -\dfrac{1}{3}\) + ... + \(\dfrac{1}{2014} -\dfrac{1}{2015}\)
= \(\dfrac{1}{4}+\dfrac{1}{2} -\dfrac{1}{2015}\)
=\(\dfrac{3}{4}- \dfrac{1}{2015} \)
\(\Rightarrow\)A<\(\dfrac{3}{4}\)(đpcm)
chúc bạn học tốt !!!! nhớ tick mình nhé