ZnO (0,1) + H2SO4 (0,1) -> ZnSO4 (0,1) + H2O
nZnO = 0,1 (mol)
\(n_{H_2SO_4}\approx0,26\left(mol\right)\)
=> sau pư, ZnO hết, H2SO4 dư
a) => mmuối = 16,1(g)
b) mdd sau pư = mZnO + \(m_{ddH_2SO_4}\) = 8,1 + 250 = 258,1(g)
\(m_{H_2SO_4dư}=25-9,8=15,2\left(g\right)\)
=> C%dd H2SO4 \(\approx5,9\%\)
C% ddZnSO4 \(\approx6,2\%\)