\(n_{Ca\left(OH\right)_2}=\dfrac{m}{M}=\dfrac{7,4}{74}=0,1mol\)
Ca(OH)2+H2SO4\(\rightarrow\)CaSO4+2H2O
\(n_{CaSO_4}=n_{H_2SO_4}=n_{Ca\left(OH\right)_2}=0,1mol\)
\(m_{CaSO_4}=0,1.136=13,6gam\)
\(m_{H_2SO_4}=0,1.98=9,8gam\)
\(m_{dd_{H_2SO_4}}=\dfrac{9,8.100}{20}=49gam\)