CH3COOH + Na --> CH3COONa + 1/2H2 (1)
C2H5OH + Na --> C2H5ONa + 1/2H2 (2)
CH3COOH + NaOH --> CH3COONa + H2O(3)
nNaOH=nCH3COOH= 0.6 (mol)
mCH3COOH= 0.6 * 60=36g
mC2H5OH= 45.2 - 36=9.2g
nC2H5OH= 0.2 (mol)
Từ (1):
=> nNa= 0.6 (mol), nH2= 0.3 (mol)
Từ (2)
=> nNa= 0.2 (mol), nH2= 0.1 (mol)
mNa= (0.6 +0.2).23= 18.4g
VH2= (0.3 + 0.1) . 22.4=8.96l
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