hh (CaO,CuO,Fe2O3)+2HCl->muoi+H2O
co so mol HCl=1,2mol->so mol H2O=0,6mol->m H2O=10,8
Bao toan khoi luong : m muoi khan=37,6 +1,2.36,5-10,8=70,6g
\(n_{HCl}=1,2\left(mol\right)\)
\(Oxit+2HCl\rightarrow Muoi+H_2O\)
__________1,2 _________0,6 ________(mol)
Bảo toàn khối lượng:
\(m_{oxit}+m_{HCl}=m_{muoi}+m_{nuoc}\)
\(=37,6+1,2.36,5=m_{muoi}+0,6.18\)
\(\Rightarrow m_{muoi}=70,6\left(g\right)\)