\(n_{Br_2}=0,5.2=1\left(mol\right)\\ C_2H_2+2AgNO_3+2NH_3\rightarrow Ag_2C_2+2NH_4NO_3\\ n_{Ag_2C_2}=\dfrac{96}{240}=0,4\left(mol\right)\\ n_{C_2H_2}=n_{Ag_2C_2}=0,4\left(mol\right)\Rightarrow m_{C_2H_2}=0,4.26=10,4\left(g\right)\\ \Rightarrow m_{hh\left(C_2H_4,C_2H_6\right)}=28-10,4=17,6\left(g\right)\\ C_2H_2+2Br_2\rightarrow C_2H_2Br_4\left(1\right)\\ C_2H_4+Br_2\rightarrow C_2H_4Br_2\left(2\right)\\ n_{Br_2\left(2\right)}=1-2.0,4=0,2\left(mol\right)\\ n_{C_2H_4}=n_{Br_2\left(2\right)}=0,2\left(mol\right)\\ m_{C_2H_4}=0,2.28=5,6\left(g\right)\\ m_{C_2H_6}=17,6-5,6=12\left(g\right)\\ hhA:\left\{{}\begin{matrix}C_2H_4:5,6\left(g\right)\\C_2H_6:12\left(g\right)\\C_2H_2:10,4\left(g\right)\end{matrix}\right.\)