a) \(\%O\left(KMnO4\right)=\frac{16.4}{158}.100\%=40,5\%\)
\(\%O\left(KClO3\right)=\frac{16.3}{122,5}.100\%=39,18\%\)
\(\Rightarrow O2\) ở KMnO4 cao hơn
b) +KMnO4
\(n_K=n_{KMnO4}=0,15\left(mol\right)\Rightarrow m_K=0,15.39=5,85\left(g\right)\)
\(n_{Mn}=n_{KMnO4}=0,15\left(mol\right)\Rightarrow m_{Mn}=0,15.55=8,25\left(g\right)\)
\(n_O=4n_{KMnO4}=0,6\left(mol\right)\Rightarrow m_O=0,6.16=9,6\left(g\right)\)
+KClO3
\(n_K=n_{KClO3}=0,15\left(mol\right)\Rightarrow m_K=0,15.39=5,85\left(g\right)\)
\(n_{Cl}=n_{KClO3}=0,15\left(mol\right)\Rightarrow m_{Cl}=0,15.35,5=5,325\left(g\right)\)
\(n_O=3n_{KClO3}=0,45\left(mol\right)\Rightarrow m_O=0,45.16=7,2\left(g\right)\)
