Zn + 2HCl → ZnCl2 + H2↑ (1)
H2 + CuO \(\underrightarrow{to}\) Cu + H2O (2)
\(n_{Zn}=\dfrac{16,25}{65}=0,25\left(mol\right)\)
Theo PT1: \(n_{H_2}=n_{Zn}=0,25\left(mol\right)\)
Theo PT2: \(n_{Cu}=n_{H_2}=0,25\left(mol\right)\)
\(\Rightarrow m_{Cu}=0,25\times64=16\left(g\right)\)