\(n_{O_2}=\frac{11,2}{22,4}=0,5\left(mol\right)\)
\(PTHH:2H_2+O_2\underrightarrow{t^o}2H_2O\)
\(\left(mol\right)\)___1_______0,5___1
a) \(m_{H_2}=1.2=2\left(g\right)\)
b) \(V_{H_2}=1.22,4=22,4\left(l\right)\)
c) \(m_{H_2O}=1.18=18\left(g\right)\)