Question

Câu2:giải các phương trình sau:

a)5(3x+2) =4x+1

b)\(\frac{4x-5}{x-1}=2+\frac{X}{X-1}\) c)\(2x^3+4x^2+2x=0\)

Answer 1

a/ \(5\left(3x+2\right)=4x+1\Leftrightarrow15x+10=4x+1\)

\(\Leftrightarrow11x=-9\Rightarrow x=-\frac{9}{11}\)

b/ ĐK: \(x\ne1\)

\(\frac{4x-5}{x-1}-\frac{2\left(x-1\right)}{x-1}-\frac{x}{x-1}=0\)

\(\Leftrightarrow4x-5-\left(2x-2\right)-x=0\)

\(\Leftrightarrow x-3=0\)

\(\Rightarrow x=3\)

c/ \(2x^3+4x^2+2x=0\)

\(\Leftrightarrow2x\left(x^2+2x+1\right)=0\)

\(\Leftrightarrow2x\left(x+1\right)^2=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)