Câu 1:
\(\dfrac{1}{3}+\dfrac{5}{12}+\dfrac{7}{18}=\dfrac{12}{36}+\dfrac{3.5}{36}+\dfrac{7.2}{36}=\dfrac{12+15+14}{36}=\dfrac{41}{36}\)Câu 2:
\(\dfrac{17}{12}-\left(\dfrac{3}{7}+\dfrac{3}{9}\right)=\dfrac{17}{12}-\dfrac{3}{7}+\dfrac{3}{9}=\dfrac{17.21}{252}-\dfrac{3.36}{252}+\dfrac{3.28}{252}=\dfrac{357-108+84}{252}=\dfrac{333}{252}=\dfrac{37}{28}\)
\(\dfrac{1}{3}+\dfrac{5}{12}+\dfrac{7}{18}=\dfrac{12}{36}+\dfrac{15}{36}+\dfrac{14}{36}=\dfrac{41}{36}\)
\(\dfrac{17}{12}-\left(\dfrac{3}{7}+\dfrac{3}{8}\right)=\dfrac{17}{12}-\dfrac{45}{56}=\dfrac{84}{252}=\dfrac{1}{3}\)