Câu 4 :
\(CT:C_nH_{2+2}\)
\(M_A=1.8125\cdot32=58\left(\dfrac{g}{mol}\right)\)
\(\Rightarrow14n+2=58\)
\(\Rightarrow n=4\)
\(CTA:C_4H_{10}\)
\(C_4H_{10}\) có 2 đồng phân
\(CH_3-CH_2-CH_2-CH_3\)
\(CH_3-CH\left(CH_3\right)-CH_3\)
Câu 5 :
\(2-clo-2metylpropan\)
\(CTsp:C_4H_9Cl\)
\(\Rightarrow Alà:C_4H_{10}\)