Question

Câu 1:Tính phần trăm khối lượng hợp chất

1,Zncl2

2,Al(oH)2

3,Na2So4

4,C2H22O11

5,HNO3

6,BaCO3

GIÚP MIK Ạ MIK CẦN GẤP!!!!

Answer 1

1. ZnCl2

MZnCl2= 65 + 35.5*2= 136g/mol

%Zn= 65/136 *100%= 47.79%

%Cl= 71/136*100%= 52.21%

2. Al(OH)3

MAl(OH)3= 27+ (16 + 1)*3=78g/mol

%Al= 27/78*100%= 24.61%

%O= 48/78*100%= 61.54%

%H= 3/78*100%= 3.85%

3. Na2SO4

MNa2SO4= 23*2+32+16*4= 142g/mol

%Na= 46/142*100%= 32.39%

%S= 32/142*100%= 22.53%

%O= 100-32.39-22.53=45.08%

4. C12H22O11

MC12H22O11= 12*12+22+16*11= 342 g/mol

%C= 144/324*100%= 42.1%

%H= 22/324*100%= 6.79%

%O= 100-42.1-6.79= 51.11%

5.HNO3

MHNO3= 1 + 14+16*3= 63g/mol

%H= 1/63*100%= 1.58%

%N= 14/63*100%= 22.22%

%O= 48/63*100%= 76.2%

6. BaCO3

MBaCO3= 137+12+48= 197g/mol

%Ba= 137/197*100%= 69.54%

%C= 12/197*100%= 6.09%

%O= 100-69.54-6.09=24.37%