Câu 1:
a: \(\left(\dfrac{1}{3}+\dfrac{2}{5}\right)\cdot\dfrac{3}{7}=\dfrac{5+11}{15}\cdot\dfrac{3}{7}=\dfrac{16}{15}\cdot\dfrac{3}{7}=\dfrac{48}{105}=\dfrac{16}{35}\)
b: \(\dfrac{5}{2}:\dfrac{1}{4}-\dfrac{1}{8}=\dfrac{5}{2}\cdot4-\dfrac{1}{8}=10-\dfrac{1}{8}=\dfrac{79}{8}\)