Câu hỏi của Khánh Linh

Question

BT3: Tìm x, biết

17) $\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750$

Mashiro Shiina · Accepted Answer

$\left(x+1\right)+\left(x+2\right)+.....+\left(x+100\right)=5750$

$\Rightarrow x+1+x+2+.....+x+100=5750$

$\Rightarrow100x+1+2+3+....+100=5750$

$\Rightarrow100x+\left[\left(\dfrac{100-1}{1}+1\right):2\right]\left(100+1\right)=5750$

$\Rightarrow100x+5050=5750$

$\Rightarrow100x=700$

$\Rightarrow x=7$Câu trả lời: $\left(x+1\right)+\left(x+2\right)+.....+\left(x+100\right)=5750$

$\Rightarrow x+1+x+2+.....+x+100=5750$

$\Rightarrow100x+1+2+3+....+100=5750$

$\Rightarrow100x+\left[\left(\dfrac{100-1}{1}+1\right):2\right]\left(100+1\right)=5750$

$\Rightarrow100x+5050=5750$

$\Rightarrow100x=700$

$\Rightarrow x=7$

Lê Mạnh Tiến Đạt · Answer

$\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750$

$\left(x+x+x+...+x\right)+\left(1+2+...+100\right)=5750$

$100x+5050=5750$

$100x=5750-5050$

$100x=700$

$x=7$

Vậy ...Câu trả lời: $\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750$

$\left(x+x+x+...+x\right)+\left(1+2+...+100\right)=5750$

$100x+5050=5750$

$100x=5750-5050$

$100x=700$

$x=7$

Vậy ...

dao thi yen nhi · Answer

100x+5050=5750

100x=5750-5050

100x=700

x=700:100

x=7Câu trả lời: 100x+5050=5750

100x=5750-5050

100x=700

x=700:100

x=7

Ôn tập toán 6