ĐKXĐ: \(x>0;x\ne1\)
\(B=\left(\frac{1}{\sqrt{x}-1}+\frac{1}{\sqrt{x}+1}\right).\left(\frac{x-1}{x}\right)\)
\(=\left(\frac{\sqrt{x}+1+\sqrt{x}-1}{x-1}\right)\left(\frac{x-1}{x}\right)=\frac{2\sqrt{x}}{x}=\frac{2}{\sqrt{x}}\)
\(A=2B\Leftrightarrow\frac{2+\sqrt{x}}{x}=\frac{2}{\sqrt{x}}\)
\(\Leftrightarrow2\sqrt{x}+x=2x\Leftrightarrow x=2\sqrt{x}\Rightarrow\left[{}\begin{matrix}\sqrt{x}=0\left(l\right)\\\sqrt{x}=2\end{matrix}\right.\) \(\Rightarrow x=4\)