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Question

bài1: tìm x:

(8 4/5x-50):40%=51

Nguyễn Lưu Vũ Quang · Accepted Answer

$\left(8\dfrac{4}{5}x-50\right):40\%=51$

$\left(\dfrac{44}{5}x-50\right):\dfrac{2}{5}=51$

$\dfrac{44}{5}x-50=51\cdot\dfrac{2}{5}$

$\dfrac{44}{5}x-50=\dfrac{102}{5}$

$\dfrac{44}{5}x=\dfrac{102}{5}+50$

$\dfrac{44}{5}x=\dfrac{352}{5}$

$x=\dfrac{352}{5}:\dfrac{44}{5}$

$x=8$

Vậy $x=8$.Câu trả lời: $\left(8\dfrac{4}{5}x-50\right):40\%=51$

$\left(\dfrac{44}{5}x-50\right):\dfrac{2}{5}=51$

$\dfrac{44}{5}x-50=51\cdot\dfrac{2}{5}$

$\dfrac{44}{5}x-50=\dfrac{102}{5}$

$\dfrac{44}{5}x=\dfrac{102}{5}+50$

$\dfrac{44}{5}x=\dfrac{352}{5}$

$x=\dfrac{352}{5}:\dfrac{44}{5}$

$x=8$

Vậy $x=8$.

Mashiro Shiina · Answer

$\left(\dfrac{84}{5x-50}\right):40\%=51$

$\dfrac{84}{5x-50}$$=51.40%$%

$\dfrac{84}{5x-50}$=$20,4$

$84=20,4(5x-50)$

$84=102x-1020$

$102x=84+1020$

$102x=1104$

$x=1104:102$

$\dfrac{184}{17}$Câu trả lời: $\left(\dfrac{84}{5x-50}\right):40\%=51$