1kg=1000g=>n c6h12o6=50/9 mol
a> c6h12o6--------> 2c2h5oh+2co2 ( enzim; 30-35độC)
50/9....................100/9........100/9 mol
m C2H5OH thu được= 100/9.46.80/100= 408,9g
b> V CO2= 100/9.22,4.80/100= 199 l
c> C2H5OH+NA---->C2H5ONA+1/2 H2
80/9------->80/9
m Na=80/9.23= 204,44 gam