a) Ta có: \(\left(-68+42\right)-\left(5042-6068\right)-\left(-2\right)^0\)
\(=-68+42-5042+6068-1\)
\(=6000-5000-1\)
\(=999\)
b) Ta có: \(29\cdot\left(19-37\right)-19\cdot\left(29-37\right)\)
\(=29\cdot19-29\cdot37-29\cdot19+19\cdot37\)
\(=-29\cdot37+19\cdot37\)
\(=37\cdot\left(-29+19\right)\)
\(=37\cdot\left(-10\right)=-370\)
c) Ta có: \(\left(-15\right)\cdot24+15\cdot\left(-75\right)-15\)
\(=\left(-15\right)\cdot24+\left(-15\right)\cdot75+\left(-15\right)\cdot1\)
\(=\left(-15\right)\cdot\left(24+75+1\right)\)
\(=-15\cdot100=-1500\)
d) Ta có: \(\frac{1}{5}+\frac{4}{7}-\frac{11}{35}\)
\(=\frac{5}{35}+\frac{20}{35}-\frac{11}{35}\)
\(=\frac{14}{35}=\frac{2}{5}\)
e) Ta có: \(\left(13\cdot95-73\right)-\left(13\cdot45+27\right)-\left(-1\right)^{2021}\)
\(=13\cdot95-73-13\cdot45-27-\left(-1\right)\)
\(=13\left(95-45\right)-\left(73+27\right)+1\)
\(=13\cdot50-100+1\)
\(=551\)
Bài 1: Tính hợp lý
a) ( - 68 + 42 ) - ( 5042 - 6068 ) - (-2)\(^0\)
= -26 - (-1026) - 1
= - 26 + 1026 - 1
= 1000 - 1
= 999
Mấy câu còn lại c hơi làm biếng, sr :<<
