\(\frac{a^3+b^3+c^3}{b^3+c^3+d^3}\\ =\frac{15^3+b^2.b+c^2.c}{b^2.b+c^2.c+3^3}\\ =\frac{3375+abc+bcd}{abc+bcd+27}\\ =\frac{3375+\left(a+d\right)bc}{27+\left(a+d\right)bc}\\ =\frac{3375+18.\frac{ac}{b}.\frac{bd}{c}}{27+18.\frac{ac}{b}.\frac{bd}{c}}\\ =\frac{3375+18.ad}{27+18ad}\\ =\frac{3375+18.15.3}{27+18.15.3}\\ =\frac{4185}{837}=5\)
Mk làm hơi dài thông cảm nha!