Question

B=121-[2^4-(4^2+889)

Answer 1

B= 121-[16-(16+889)]

B= 121-[16-905]

B= 121+889

B= 1010

Answer 2

Giải:

\(B=121-\left[2^4-\left(4^2+889\right)\right]\)

\(\Leftrightarrow B=121-\left[16-\left(16+889\right)\right]\)

\(\Leftrightarrow B=121-16+16+889\)

\(\Leftrightarrow B=121+889\)

\(\Leftrightarrow B=1010\)