Ta có : (12+13+14+....+110)×x=19+28+....+82+91(12+13+14+....+110)×x=19+28+....+82+91
Đặt A=19+28+....+82+91A=19+28+....+82+91
=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)
=1+102+103+...+109=102+103+....+109+1010=1+102+103+...+109=102+103+....+109+1010
=(12+13+14+....+110)×10=(12+13+14+....+110)×10 (1)
Từ (1), suy ra:
(12+13+14+...+110)×x=(12+13+14+....+110)×10(12+13+14+...+110)×x=(12+13+14+....+110)×10
⇒x=10⇒x=10
Vậy x=10x=10
~ Học tốt ~
Ta có : (12+13+14+....+110)×x=19+28+....+82+91(12+13+14+....+110)×x=19+28+....+82+91
Đặt A=19+28+....+82+91A=19+28+....+82+91
=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)=(9−1−1−....−1)+(82+1)+(73+1)+.....+(19+1)
=1+102+103+...+109=102+103+....+109+1010=1+102+103+...+109=102+103+....+109+1010
=(12+13+14+....+110)×10=(12+13+14+....+110)×10 (1)
Từ (1), suy ra:
(12+13+14+...+110)×x=(12+13+14+....+110)×10(12+13+14+...+110)×x=(12+13+14+....+110)×10
⇒x=10⇒x=10
Vậy x=10x=10
~ Học tốt ~
