a) Ta có: \(\dfrac{x}{14}-\dfrac{1}{7}=\dfrac{-3}{4}\)
\(\Leftrightarrow\dfrac{x}{14}=\dfrac{-3}{4}+\dfrac{1}{7}=\dfrac{-21}{28}+\dfrac{4}{28}=\dfrac{-17}{28}\)
hay \(x=\dfrac{-17\cdot14}{28}=\dfrac{-17}{2}\)
Vậy: \(x=-\dfrac{17}{2}\)
\(a)\dfrac{x}{14}-\dfrac{1}{7}=\dfrac{-3}{4}\)
\(\dfrac{x}{14}=\dfrac{-3}{4}+\dfrac{1}{7}\)
\(\dfrac{x}{14}= \dfrac{-17}{28}\)
\(x=\dfrac{14.(-17)}{28}\)
\(x=\dfrac{-17}{2}\)
\(b)x-\dfrac{1}{8}=\dfrac{5}{8}\)
\(x=\dfrac{5}{8}+\dfrac{1}{8}\)
\(x=\dfrac{6}{8}=\dfrac{3}{4}\)
\(c)\dfrac{1}{5}+\dfrac{1}{11}<\dfrac{x}{55}<\dfrac{2}{5}+\dfrac{1}{55}(xthuộc Z )\)
\(\Rightarrow \dfrac{11}{55}+\dfrac{5}{55}<\dfrac{x}{55}<\dfrac{22}{55}+\dfrac{1}{55} \)
\(\Rightarrow \dfrac{16}{55}<\dfrac{x}{55}<\dfrac{23}{55}\)
\(\Rightarrow 21< x < 23\)
\(\Rightarrow x=22\)