Ta có: \(3,7a\left(X+16\right)=a.\left(X+62.2\right)\\ \Rightarrow3,7\left(X+16\right)=X+62.2\\ \Rightarrow X=24\left(Mg\right)\\ \Rightarrow CTHHhaihợpchất:MgO;Mg\left(NO_3\right)_2\)
Bài này chúng ta có thể làm theo cách sau nha!
\(G.sử:a=1\left(mol\right)\\ m_{XO}=\left(M_X+16\right)\left(g\right)\\ m_{X\left(NO_3\right)_2}=\left(M_X+124\right)\left(g\right)\\ Vì:\dfrac{m_{X\left(NO_3\right)_2}}{m_{XO}}=3,7\\ \Leftrightarrow\dfrac{M_X+124}{M_X+16}=3,7\\ \Leftrightarrow M_X=24\left(\dfrac{g}{mol}\right)\\ \Rightarrow X:Magie\left(Mg\right)\\ HC:MgO,Mg\left(NO_3\right)_2\)
