Mk ko chép lại đề nhá
a)
\(1\frac{3}{4}x=3\frac{1}{3}+5\)
\(1\frac{3}{4}x=3\frac{1}{3}+4\frac{3}{3}\)
\(1\frac{3}{4}x=7\frac{4}{3}\)
\(\frac{7}{4}x=\frac{25}{3}\)
\(x=\frac{25}{3}:\frac{7}{4}\)
\(x=\frac{25}{3}.\frac{4}{7}\)
\(x=\frac{100}{21}\)
b)
\(\frac{1}{3}.\frac{1}{3}x=-5-\frac{1}{4}\)
\(\frac{1}{3}.\frac{1}{3}x=\frac{-20}{4}+\frac{-1}{4}\)
\(\frac{1}{9}x=\frac{-21}{4}\)
\(x=\frac{-21}{4}:\frac{1}{9}\)
Đến đây bạn tự giải nhé!
c)
\(2x^2=0+72\)
\(2x^2=72\)
\(x^2=72:2\)
\(x^2=36\)
\(x^2=6^2\)
⇒ x = 6