\(\dfrac{4}{9}:\dfrac{11}{15}+\dfrac{4}{9}.\dfrac{18}{11}-\dfrac{1}{3}\)
= \(\dfrac{4}{9}.\dfrac{15}{11}+\dfrac{4}{9}.\dfrac{18}{11}-\dfrac{1}{3}\)
= \(\dfrac{4}{9}.\left(\dfrac{15}{11}+\dfrac{18}{11}\right)-\dfrac{1}{3}\)
= \(\dfrac{4}{9}.3-\dfrac{1}{3}\)
= \(\dfrac{4}{3}-\dfrac{1}{3}\)
= 1