\(42x-3=32x+4\)
\(\Rightarrow42x-32x=3+4\)
\(\Rightarrow10x=7\)
\(\Rightarrow x=\frac{7}{10}\)
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Bình luận (2)
\(42x-3=32x+4\)
\(\Rightarrow42x-32x=3+4\)
\(\Rightarrow10x=7\)
\(\Rightarrow x=\frac{7}{10}\)
(3x-2)3=125
xεN
(x-3)6=(x-3)4
xεN
x εN
5x+3-5x=175
42x-3=32x+4
x εN
42x-3=32x+4
x εN
Tìm x
a) 5x = 125
b) 32x = 81
c) 52x-3 – 2.52 = 52 .3
a) 27^x-1= 9x+1
b) 16^x+1=32x-2
32x +9+7 =11 giúp mình với
5\(x\) -3 = 4x + 6
7 - 2x = 4x - 67