Ta có: \(3\frac{1}{3}+7\frac{3}{17}\cdot\frac{2}{15}-2\frac{3}{17}\cdot\frac{2}{15}\)
\(=\frac{10}{3}+\frac{122}{17}\cdot\frac{2}{15}-\frac{37}{17}\cdot\frac{2}{15}\)
\(=\frac{10}{3}+\frac{244}{255}-\frac{74}{255}\)
\(=\frac{10}{3}+\frac{2}{3}=\frac{12}{3}=4\)