`34+2(x-5)^2=66`
`=>2(x-5)^2=66-34`
`=>2(x-5)^2=32`
`=>(x-5)^2=32:2`
`=>(x-5)^2=16=(4)^2=(-4)^2`
`=>` $\left[ \begin{array}{l}x-5=4\\x-5=-4\end{array} \right.$
`=>` $\left[ \begin{array}{l}x=9\\x=1\end{array} \right.$
Vậy x=9 hoặc x=1
Ta có: \(34+2\left(x-5\right)^2=66\)
\(\Leftrightarrow2\left(x-5\right)^2=32\)
\(\Leftrightarrow\left(x-5\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=4\\x-5=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=9\\x=1\end{matrix}\right.\)
Vậy: \(x\in\left\{1;9\right\}\)