\(3^{2x+1}=27\)
\(\Rightarrow3^{2x+1}=3^3\)
\(\Rightarrow2x+1=3\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(3^{2x+1}=27\)
\(\Rightarrow3^{2x}.3=27\)
\(\Rightarrow3^{2x}=27:3\)
\(\Rightarrow3^{2x}=9\)
\(\Rightarrow3^{2x}=3^2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
Vậy x = 1
32x+1= 27
32x+1= 33
=> 2x+1=3
2x= 3-1
2x= 2
x= 2 : 2
x=1