Question

(2y+1).(3-y)=0

y . (3y-2)=0

các bạn ơi giúp mk vơi chiều mk đi học rồi

Answer 1

\(y\left(3y-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}y=0\\3y-2=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}y=0\\3y=2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}y=0\\y=\dfrac{2}{3}\end{matrix}\right.\)

Answer 2

a, \(\left(2y+1\right)\left(3-y\right)=0\Rightarrow\left[{}\begin{matrix}2y+1=0\\3-y=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}y=\dfrac{-1}{2}\\y=3\end{matrix}\right.\)

\(\Rightarrow y=\left\{\dfrac{-1}{2};3\right\}\)

b, \(y\left(3y-2\right)=0\Rightarrow\left[{}\begin{matrix}y=0\\3y-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}y=0\\y=\dfrac{2}{3}\end{matrix}\right.\)

\(\Rightarrow y=\left\{0;\dfrac{2}{3}\right\}\)

Answer 3

\(\left(2y+1\right)\left(3-y\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2y+1=0\\3-y=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}y=\dfrac{-1}{2}\\y=3\end{matrix}\right.\)

Answer 4