=>(2x-1)(x-1)=(2x-3)(x-2)
=>2x^2-2x-x+1=2x^2-4x-3x+6
=>-3x+1=-7x+6
=>4x=5
=>x=5/4
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Bài 3: Phương trình đưa được về dạng ax + b = 0
Các câu hỏi tương tự
a)5-(x-6)=4(3-2x)
b)2x(x+2)2-8x2=2(x-2)(x2+2x+4)
c)7-(2x+4)=-(x+4)
d)(x-2)3+(3x-1)(3x+1)=(x+1)3
e)(x+1)(2x-3)=(2x-1)(x+5)
f)(x-1)3-x(x+1)2=5x(2-x)-11(x+2)
g)(x-1)-(2x-1)=9-x
h)(x-3)(x+4)-2(3x-2)=(x+4)2
i)x(x+3)2-3x=(x+2)33+11
j)(x+1)(x2-x+1)-2x=x(x+1)(x-1)
a.(x+5)(2x-1)=(2x-3)(x+1)
b.(x+1)(x+9)=(x+3)(x+5)
c.(3x+5)(2x+1)=(6x-2)(x-3)
d.(x-2)(3x+5)=(2x-4)(x+1)
đ.9x2 -1=(3x+1)(2x-3)
e.(2x+5)(x-4)=(x-5)(4-x)
Câu 1: Giải các phương trình sau:
a) 3x-2(x-3)=0
b) (x+1) (2x-3) = ( 2x -1) (x +5)
c) 2x/ x-1 -x/x+1 =1
d) (2x +3) (3x-5)=0
e) x-2/x+2-3/x-2 = 2(x-11)/ x2
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25 tháng 1 2022 lúc 20:31
4,dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}5,dfrac{2x}{3}+dfrac{2x-1}{6}4-dfrac{x}{3}6,dfrac{x-1}{2}+dfrac{x-1}{4}1-dfrac{2left(x-1right)}{3}
Đọc tiếp
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
1) Phương trình dạng ax+b=0
1) 2x+x+12=0
2) x-5=3-x
3)2x-(3-5x)=4(x+3)
4)2x+3/3=5-4x/2
5) x-3/5=6- 1-2x/3
6) 3x-2/6 -5=3-2(x+7)/4
7) 3x-7/2+ x+1/3= -16
8) x- x+1/3=2x+1/5
giải phương trình sau
1. (2x-3)(2x+3)-4(x+5)^2= -9(1+5x)
2. 2x(x+5)=(x+3)^2+(x-1)^2+20
3.(x+2)^3-(x-2)^3=12x(x-1)-8
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
Bài 1 : Giải các phương trình sau :
1) (x – 2)(x – 5) (x – 3)(x – 4)
2) ( 6x + 2)(x – 2) 2x(3x – 5)
3) (x – 2) 2 (x – 3)(x + 2)
4) (x–1)(x +3) – (x+2)(x–3) 0
5) (x–2)(x –5) – (x–3)(x–4) 0
6) (3x – 2)(4x + 3) 2x(6x – 1)
7) 4x 2 – (2x + 1)(2x – 1) 0
8) (4x–5)(x+3) (2x – 3)(7+2x)
9) (x + 3)(x – 2) (x + 1) 2
10) (x+7)(x–7) + x 2 – 2 2(x 2 +5)
11) (x–1) 2 + (x+3) 2 2(x– 2)(x+2)
12) (x – 5) 2 (x + 3) 2 + 2
13) (3x + 2) 2 – (3x – 2) 2 5x + 38
Đọc tiếp
Bài 1 : Giải các phương trình sau :
1) (x – 2)(x – 5) = (x – 3)(x – 4)
2) ( 6x + 2)(x – 2) = 2x(3x – 5)
3) (x – 2) 2 = (x – 3)(x + 2)
4) (x–1)(x +3) – (x+2)(x–3) = 0
5) (x–2)(x –5) – (x–3)(x–4) = 0
6) (3x – 2)(4x + 3) = 2x(6x – 1)
7) 4x 2 – (2x + 1)(2x – 1) = 0
8) (4x–5)(x+3) = (2x – 3)(7+2x)
9) (x + 3)(x – 2) = (x + 1) 2
10) (x+7)(x–7) + x 2 – 2 = 2(x 2 +5)
11) (x–1) 2 + (x+3) 2 = 2(x– 2)(x+2)
12) (x – 5) 2 = (x + 3) 2 + 2
13) (3x + 2) 2 – (3x – 2) 2 = 5x + 38