Question

2\(\dfrac{1}{3}\) - 125% . x = \(\dfrac{1}{4}\)

Answer 1

\(2\dfrac{1}{3}-125\%.x=\dfrac{1}{4}\)

⇒ \(\dfrac{7}{3}-\dfrac{125}{100}.x=\dfrac{1}{4}\)

⇒ \(\dfrac{5}{4}x=\dfrac{28}{12}-\dfrac{3}{12}\)

⇒ \(\dfrac{5}{4}x=\dfrac{25}{12}\)

⇒ \(x=\dfrac{25}{12}.\dfrac{4}{5}\)

⇒ \(x=\dfrac{100}{60}\) \(=\dfrac{5}{3}\)

Vậy \(x=\dfrac{5}{3}\).

Answer 2

\(2\dfrac{1}{3}\) - 125% . x = \(\dfrac{1}{4}\)

=> \(\dfrac{7}{3}\) - \(\dfrac{125}{100}\) . x = \(\dfrac{1}{4}\)

=> \(\dfrac{5}{4}x\) = \(\dfrac{28}{12}\) - \(\dfrac{3}{12}\)

=> \(\dfrac{5}{4}x\) = \(\dfrac{25}{12}\)

=> \(\dfrac{25}{12}\). \(\dfrac{4}{5}\)

=> \(\dfrac{100}{60}\)\(=\dfrac{5}{3}\)

x = \(\dfrac{5}{3}\)