Giải:
\(\left(\dfrac{1}{4}+\dfrac{11}{9}\right):\dfrac{34}{5}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right):\dfrac{34}{5}\)
\(=\left(\dfrac{1}{4}+\dfrac{11}{9}\right).\dfrac{5}{34}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right).\dfrac{5}{34}\)
\(=\left[\left(\dfrac{1}{4}+\dfrac{11}{9}\right)+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right)\right].\dfrac{5}{34}\)
\(=\left[\dfrac{1}{4}+\dfrac{11}{9}-\dfrac{2}{9}+\dfrac{29}{4}\right].\dfrac{5}{34}\)
\(=\left[\dfrac{9}{9}+\dfrac{30}{4}\right].\dfrac{5}{34}\)
\(=\left[1+\dfrac{15}{2}\right].\dfrac{5}{34}\)
\(=\dfrac{17}{2}.\dfrac{5}{34}\)
\(=\dfrac{5}{4}\)
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