Question

1 TÍNH

\(a,\left(\frac{-1}{4}\right)^0\)

\(b,\left(-2\frac{1}{3}\right)^2\)

\(c,\left(\frac{4}{5}\right)^{-2}\)

\(d,\left(0,5\right)^{-3}\)

\(e,\left(-1\frac{1}{3}\right)^4\)

\(f,27^3:3^2\)

\(g,\left(\frac{3}{5}\right)^{15}:\left(\frac{9}{25}\right)^5\)

\(h,5-\left(-\frac{5}{11}\right)^0+\left(\frac{1}{3}\right)^2:3\)

\(i,\left(\frac{1}{3}\right)^{-3}+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2:\frac{1}{2}\right].8\)

Answer 1

a) \(\left(-\frac{1}{4}\right)^0=1\)

b) \(\left(-2\frac{1}{3}\right)^2=\left(-\frac{7}{3}\right)^2=\frac{49}{9}\)

c) \(\left(\frac{4}{5}\right)^{-2}=\frac{25}{16}\)

d) \(\left(0,5\right)^{-3}=8\)

e) \(\left(-1\frac{1}{3}\right)^4=\left(-\frac{4}{3}\right)^4=\frac{256}{81}\)

Answer 2

a, \(\left(\frac{-1}{4}\right)^0\) = 1

Bất kỳ số nguyên nào nếu có mũ bằng 0 đều bằng 1

b, \(\left(-2\frac{1}{3}\right)^2=\left(-\frac{7}{3}\right)^2=\frac{49}{9}\)