Ta có : \(n_{H2}=2,2\left(mol\right)\)
\(PTHH:2 K M n O 4 → K 2 Mn O 4 + M n O 2 + O 2\)
......................x........................................................0,5x
\(\text{2 K C l O 3 → 2KCl + 3 O 2}\)
y.......................................1,5y
Giải hệ PT:
\(\left\{{}\begin{matrix}158x+122,5y=273,4\\0,5x+1,5y=2,2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,8\\y=1,2\end{matrix}\right.\)
\(\%KMnO4=\frac{158.0,8}{273,4}.100\%=46,32\%\)
\(\%KClO3=100\%-\text{46.32%= 53.68%}\)