\(a,n_{CO_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\)
\(n_{CO_2}=0,5.44=11\left(g\right)\)
\(b,n_{NH_3}=\dfrac{10,08}{22,4}=0,45\left(mol\right)\)
\(n_{NH_3}=0,45,17=7,65\left(g\right)\)
\(c,n_{NO_2}=\dfrac{16,8}{22,4}=0,75\left(mol\right)\)
\(n_{NO_2}=0,75.46=34,5\left(g\right)\)