Ta có: \(\left\{{}\begin{matrix}n_{OH^-}=0,1+0,1\cdot2=0,3\left(mol\right)\\n_{CO_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\) Tạo 2 muối
PT: \(CO_2+OH^-\rightarrow HCO_3^-\)
a_____a_________a (mol)
\(CO_2+2OH^-\rightarrow CO_3^{2-}+H_2O\)
b____2b________b (mol)
Ta lập HPT: \(\left\{{}\begin{matrix}a+b=0,2\\a+2b=0,3\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}a=0,1\\b=0,1\end{matrix}\right.\)
Mặt khác: \(n_{Ba^{2+}}=0,1\left(mol\right)=n_{CO_3^{2-}}=n_{BaCO_3}\) \(\Rightarrow m_{BaCO_3}=0,1\cdot197=19,7\left(g\right)\)
