Question

1,

A=\(3\sqrt{8}-\sqrt{50}-\sqrt{\sqrt{2}-1}\)

B=2\(\dfrac{2}{x-1}\sqrt{\dfrac{x^2-2x+1}{4x^2}}\) với 0<x<1

2,Giải pt

\(\sqrt{x^2-3x+2}+\sqrt{x+2}=\sqrt{x+2}+\sqrt{x^2+2x+3}\)

Answer 1

\(A=3\sqrt{8}-\sqrt{50}-\sqrt{\sqrt{2}-1}\)

\(\Leftrightarrow6\sqrt{2}-5\sqrt{2}-\sqrt{\sqrt{2}-1}\)

\(\Leftrightarrow\sqrt{2}-\sqrt{\sqrt{2}-1}\)

\(B=2.\dfrac{2}{x-1}.\sqrt{\dfrac{x^2-2x+1}{4x^2}}\)

\(\Leftrightarrow\)\(\dfrac{2}{x-1}.\dfrac{\sqrt{x^2-2x+1}}{2x}\)

\(\Leftrightarrow\)\(\dfrac{2}{x-1}.\dfrac{\sqrt{\left(x-1\right)^2}}{x}\)

\(\Leftrightarrow\)\(\dfrac{2}{x-1}.\dfrac{x-1}{x}\)

\(\Leftrightarrow\)\(2.\dfrac{1}{x}\)

\(\Leftrightarrow\)\(\dfrac{2}{x}\)