Question

1, \(a, \sqrt{3x-5} = \sqrt{7x-1} \)

\(b, \sqrt{5x-7}=m \) Biện luận theo m

\(c, \sqrt{x-3} + \sqrt{13-x} =2\sqrt{5}\)

\(d, \sqrt{x-2} + \sqrt{4-x} = x^{2} -6x+11 \)

\(e, \sqrt[3]{x-7} + \sqrt[3]{x-3} =\sqrt[6]{(x-3)(x-7)}\)

\(f, \sqrt[3]{x-1} + \sqrt[3]{x+1} =\sqrt[3]{5x}\)

\(g, \sqrt[3]{x+5} + \sqrt[3]{x+6} =\sqrt[3]{2x+11}\)

h, \(\sqrt[3]{(x-2)^{2}} + \sqrt[3]{(x+7)^{2}} - \sqrt[3]{(2-x)(x+7)}\)

\(k, \sqrt{\dfrac{x}{2x-1}} +\sqrt{\dfrac{2x-1}{x}} = 2\)

MN THÔNG CẢM R GIÚP EM VỚI Ạ

Answer 1

a, Điều kiện x ∉ {\(\frac{5}{3};\frac{1}{7}\)}

\(\sqrt{3x-5}=\sqrt{7x-1}\)

\(\left(\sqrt{3x-5}\right)^2=\left(\sqrt{7x-1}\right)^2\)

\(\left|3x-5\right|=\left|7x-1\right|\)

\(3x-5=7x-1\)

\(-4x=4\) => x = -1