a/ k mở nên mđ: R1ntR3
=> I=IA=I1=I3= 2,4 (A)
=> Rtđ= U/I= 24/2,4= 10(\(\Omega\) )
=> R1= Rtđ-R3= 10-8= 2(\(\Omega\) )
=> U1= I1.R1= 2,4.2= 4,8(V)
=> U3= 2,4.8= 19,2(V)
b/ k đóng mđ: (R1//R2)ntR3
=> IA=I1= 2 (A)
=> U1=U2= I1.R1= 2.2= 4(V)
=> U3= U-U12= 24-4= 20(V)
=>I= I3= U3/R3= 20/8= 2,5 (A)
=> I2= I-I1= 2,5-2= 0,5 (A)
=> R2= U2/I2= 4/0,5= 8(\(\Omega\) )